What is the derivative of #sqrt(5x)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Nlyyildirim Jul 12, 2016 #=5/(2sqrt(5x))# or #sqrt5/(2sqrt(x))# Explanation: #sqrt(5x)=(5x)^(1/2)# #d/dx(ax)^n=n*(ax)^(n-1)*a# derivative of #(5x)^(1/2)=1/2*(5x)^(1/2-1)*5# #=5/2*(5x)^(-1/2)*# #=5/2*1/sqrt(5x)# #=5/(2sqrt(5x))# or #sqrt5/(2sqrt(x))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 25045 views around the world You can reuse this answer Creative Commons License