What is the polar form of $(1,18)$ ?

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Answer 1 · 2016-06-01T20:36:43

$(r,theta)=(5sqrt(13),arctan(18))$

Given Cartesian coordinates $(x,y)$ in Quadrant I

$r=sqrt(x^2+y^2)$
and
$theta=arctan(y/x)$

Answer 2 · 2016-06-01T20:49:20

(18, 1.5)

Polar format: (r, $theta$ )

$r=sqrt(x^2+y^2)$

$theta = tan^-1(y/x)$

apply both formulas when going from Cartesian -> polar

$sqrt(1^2+18^2) = sqrt(325) ~~ 18.0$

$theta = tan^-1(18/1) = tan^-1(18) ~~ 1.5 radians$

Thus our answer of:

Polar format of (1,18) Cartesian is:

(18, 1.5)

What is the polar form of (1,18)(1,18)?