How do you find the polar coordinates of the point $(- 2, 0)$ $(-2,0)$ ?

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How do you find the polar coordinates of the point $(- 2, 0)$ $(-2,0)$ ?

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Answer 1 · 2014-09-11T11:07:32

The polar coordinates of $(x, y) = (- 2, 0)$ $(x,y)=(-2,0)$ is $(r, θ) = (2, π)$ $(r,theta)=(2,pi)$ .

Since the distance of the point from the origin is $\sqrt{{(- 2)}^{2} + {(0)}^{2}} = 2$ $sqrt{(-2)^2+(0)^2}=2$ ,
so $r = 2$ $r=2$ .

Since the line segment (vector) from the origin to (-2,0) and
the positive x-axis makes $180^{\circ}$ $180^circ$ , whcih is $π$ $pi$ radians; therefore, $θ = π$ $theta=pi$ .

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How do you find the polar coordinates of the point $(- 2, 0)$ $(-2,0)$ ?

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How do you find the polar coordinates of the point (−2,0)(-2,0) ?

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How do you find the polar coordinates of the point $(- 2, 0)$ $(-2,0)$ ?