How do you solve #x + 8 - 1> x/3 #?

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Answer 1 · 2016-05-24T03:38:59

#x> -21/2#

Given,

#x+8-1>x/3#

Simplify the left side.

#x+7>x/3#

Multiply both sides by #3#.

#color(red)(3(color(black)(x+7)))>color(red)(3(color(black)(x/3)))#

Simplify.

#3x+21>x#

Subtract #3x# from both sides.

#3xcolor(white)(i)color(red)(-3x)+21>xcolor(white)(i)color(red)(-3x)#

#21> -2x#

Divide both sides by #-2#

#color(red)(color(black)(21)/-2)> color(red)((color(black)(-2x))/-2)#

#x<-21/2#

Since you divided by a negative number, flip the inequality sign.

#x> color(green)(|bar(ul(color(white)(a/a)color(black)(-21/2)color(white)(a/a)|)))#