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If 2#cos^2x# - #cosx# = 1 , what is the value of #x#?

1 Answer

Apr 2, 2016

#x=0#

Explanation:

As we know:

#cos 0 =1#

Put #x=0# in equation:

#2cos^(2)0-cos0=1#

#2*1-1=1#

#1=1#

#L.H.S=R.H.S#

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