What is the graph of $y=sin(x/2)$ ?

Question

5031 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-10-06T05:00:09

First, calculate the period.

$omega=(2pi)/B=(2pi)/(1/2)=((2pi)/1)*(2/1)=4pi$

Break up $6pi$ into fourth by dividing by $4$ .

$(4pi)/(4)=pi$

$0,pi,2pi,3pi,4pi ->x$ -values

These $x$ values correspond to ...

$sin(0)=0$

$sin((pi)/(2))=1$

$sin(pi)=0$

$sin((3pi)/2)=-1$

$sin(2pi)=0$

Enter the function using the Y= button

enter image source here

Press the WINDOW button.
Enter the Xmin of $0$ and Xmax of $4pi$ .
The calculator converts $4pi$ to its decimal equivalent.

enter image source here

Press the GRAPH button.

enter image source here

What is the graph of y=sin(x/2)y=sin(x/2)?