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What is the derivative of #sin(x^2 -2)^3#?

1 Answer

Mar 29, 2016

#d/dxsin(x^2-2)^3=6x(x^2-2)^2cos(x^2-2)^3#.

Explanation:

By using the power rule in conjunction with other rules we get

#d/dxsin(x^2-2)^3=cos(x^2-2)^3*3(x^2-2)^2*2x#

#=6x(x^2-2)^2cos(x^2-2)^3#.

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