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How do you find the derivative of #-2x(x^2+3)^-2#?

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Bdub · Shwetank Mauria

Mar 17, 2016

#d/dx=(6x^2-6)/((x^2+3)^3#

Explanation:

#f=-2x,g=(x^2+3)^-2#

#f'=-2,g'=-2(x^2+3)^-3 *2x#

#(df)/(dx)=(8x^2)/(x^2+3)^3 -2/((x^2+3)^2#

#(df)/(dx)=(8x^2-2(x^2+3))/((x^2+3)^3#

#(df)/(dx) = (8x^2-2x^2-6)/((x^2+3)^3#

#(df)/(dx)=(6x^2-6)/((x^2+3)^3#

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