How do you solve $3.5 (x - \frac{8}{4}) = 2.8$ $3.5(x-8/4) = 2.8$ ?

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How do you solve $3.5 (x - \frac{8}{4}) = 2.8$ $3.5(x-8/4) = 2.8$ ?

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Answer 1 · 2016-02-19T12:31:02

$x = \frac{14}{5}$ $x=14/5$

Explanation:

Simplify 8/4 to 2.

$3.5 (x - 2) = 2.8$ $3.5(x-2)=2.8$

Divide both sides by 3.5

$x - 2 = 0.8$ $x-2=0.8$

Add 2 to both sides.

$x = 2.8 = \frac{14}{5}$ $x=2.8=14/5$

Answer 2 · 2016-02-19T12:34:32

$x = 2 \frac{4}{5}$ $x=2 4/5$

Explanation:

First do the easy bit and replace $\frac{8}{4}$ $8/4$ with $2$ $2$

$XXX 3.5 (x - 2) = 2.8$ $color(white)("XXX")3.5(x-2)=2.8$

Divide both sides by $3.5$ $3.5$
(this is easier if you notice $3.5 = 7 \times 0.5$ $3.5=7xx0.5$ and $2.8 = 7 \times 0.4$ $2.8=7xx0.4$ )
$XXX (x - 2) = \frac{4}{5}$ $color(white)("XXX")(x-2)= 4/5$

Add $2$ $2$ to both sides:
$XXX x = 2 \frac{4}{5}$ $color(white)("XXX")x= 2 4/5$ (or $\frac{14}{5}$ $14/5$ )

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How do you solve $3.5 (x - \frac{8}{4}) = 2.8$ $3.5(x-8/4) = 2.8$ ?

2 Answers

Explanation:

Explanation:

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