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What is the derivative of #-sin^2(x)#?

1 Answer

Feb 19, 2016

#f'(x)=-sin2x#

Explanation:

Given equation is #f(x)=-sin^2(x)#
We will use chain rule here.

So, #f'(x)=-d/dx(sin^2(x))=-2sinxd/dx(sinx)=-2sinxcosx#

Simplifying the above equation gives you the answer.

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