How do you find the derivative of $sqrt(2x+3)$ ?

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Answer 1 · 2016-01-03T14:51:09

The derivative of this function is $1/(sqrt(2x+3))$ .

Let $h(x) = sqrt(2x+3)$ . You see that that $h = f @ g$ with $f(x) = sqrtx$ and $g(x) = 2x+3$ .

By the chain rule, $h'(x) = g'(x)*(f'@g)(x) = g'(x)*f'(g(x))$ .

Here, $f'(x) = 1/(2sqrtx)$ and $g'(x) = 2$ .

So $h'(x) = 2*1/(2sqrt(2x+3)) = 1/(sqrt(2x+3))$

How do you find the derivative of sqrt(2x+3)sqrt(2x+3)?