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What is the derivative of #lnx / x#?

1 Answer

Dec 24, 2015

Using quotient rule, which states that for #y=f(x)/g(x)#, #(dy)/(dx)=(f'(x)g(x)=f(x)g'(x))/g(x)^2#

Explanation:

Solving:

#(dy)/(dx)=((1/x)x-lnx(1))/x^2#

#(dy)/(dx)=(1-lnx)/x^2#

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