How do you solve the inequality $2 (4 - n) < 3 n$ $2(4-n) < 3n$ ?

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Answer 1 · 2015-12-16T22:48:05

$\frac{8}{5} < n$ $8/5 < n$

To solve inequalities, solve like you would an equation.

Original equation:
$2 (4 - n) < 3 n$ $2(4-n) < 3n$

Distribute the $2$ $2$ :
$8 - 2 n < 3 n$ $8-2n < 3n$

Add $2 n$ $2n$ to both sides:
$8 < (3 n + 2 n)$ $8 < (3n+2n)$
$8 < 5 n$ $8 < 5n$

Divide to get $n$ $n$ by itself:
$\frac{8}{5} < n$ $8/5 < n$

Final Answer:
$\frac{8}{5} < n$ $8/5 < n$

How do you solve the inequality 2(4−n)<3n2(4-n) < 3n?