How do you differentiate $f (x) = 5 ln (\frac{sin x}{x})$ $f(x)= 5ln(sinx/x)$ ?

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Answer 1 · 2015-11-16T18:31:39

The derivative is $f'(x) = (xcosx - sinx)/(xsinx)$

The derivative of $sinx/x$ is taken using quotient rule and multiplied with the derivative of $lnu$ where $u= sinx/x$ which is $1/u$ .

Hope that helps,
Cheers.

How do you differentiate f(x)= 5ln(sinx/x) f(x)=5ln(sinxx)f(x)= 5ln(sinx/x) ?