What is the derivative of $f(x)=sec(ln(1/x))$ ?

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Answer 1 · 2015-11-13T10:16:31

The derivative would be $-1/x . sec(ln(1/x)). tan(ln(1/x))$

Always treat problem such as this like the following. Break this problem into three parts:

$w = sec(y)$ where $y= ln u$ where $u=1/x$ so the derivative of this function would be:

$f'(x) = u' . y ' . w'$

Derivate the functions separately and then multiply them with each other. Finally substitute the with the original variables.

Hope that helps,
Cheers.

What is the derivative of f(x)=sec(ln(1/x))f(x)=sec(ln(1/x))?