How do you solve #-4x+8<1/2x +3#?

1 Answer
Eivind K.
Nov 7, 2015
  • Multiply by #2# to get rid of denominators and isolate the #x#'s
  • Divide by the coifficient of x on both sides
    #x > 10/9#

Explanation:

Start off by multiplying by #2# to get rid of denominators
#-4x + 8 < 1/2x + 3 to -8x + 16 < x + 6#
NOTE: We are multiplying by #2# since #2# is the highest common denominator.

Isolate the x's:
#-8x - x < 6 - 16#

..add
#-9x < -10#

Divide by -9. NOTE: Turn the "is larger than" sign when you are dividing (or multiplying) by a negative number.

#(-9x)/-9 > -10/-9 to (cancel(-9)x)/(cancel(-9)) > (-10)/-9 to x > 10/9#

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