How do you graph using the intercepts for #-4x-14y=28#?

1 Answer
Ip1201
Nov 4, 2015

Simplify it and use the formulas; for x-intercept, y=0 and vice versa.

Explanation:

#-4x - 14y = 28#
#-14y= 4x +28#
#y= -2/7 x-2#

Using the formulas, substitute, and you can get #-7# for your #x# intercept. Since I have written my equation in slope intercept form, (#y=mx+b#), my #b# is my #y# intercept, #-2#.

Since you have your intercepts, plot the two points and connect.

(0, -2) and (-7, 0) graph{-14y=4x+28 [-10, 10, -5, 5]}

Related questions
See all questions in Graphs Using Slope-Intercept Form
Impact of this question
2376 views around the world
You can reuse this answer
Creative Commons License