How do you differentiate #((9y^2)(-2y^2))/(7y^4)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Alan P. Apr 13, 2015 #((9y^2)(-1y^2))/(7y^4)# #= (-18y^4)/(7y^4)# #=-(18)/(7)# The derivative of any constant is #0# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 2071 views around the world You can reuse this answer Creative Commons License