How do you use the quotient rule to find the derivative of y=(x-sqrt(x))/(x^(1/3)) ?
1 Answer
Sep 8, 2014
y'=2/3*1/x^(1/3)-1/6*1/x^(5/6) Solution:
y=(x−sqrtx)/x^(1/3)
y=x/x^(1/3)-x^(1/2)/x^(1/3)
y=x^(2/3)-x^(1/6) differentiating with respect to
x ,
y'=2/3x^(2/3-1)-1/6x^(1/6-1)
y'=2/3x^(-1/3)-1/6x^(-5/6)
y'=2/3*1/x^(1/3)-1/6*1/x^(5/6)
