How do you find the derivative of y= root3(e^x+1)y=3√ex+1 ?
1 Answer
Sep 15, 2014
y'=1/3(e^x+1)^(-2/3)*e^x Explanation :
y=(e^x+1)^(1/3) let's
y=(f(x))^(1/3) , then from Chain Rule,
y'=1/3(f(x))^(-2/3)f'(x) Similarly following for the give problem and using Chain Rule, yields
y'=1/3(e^x+1)^(-2/3)*e^x
