How do you find the derivative of $y= 10^(1-x^2)$ ?

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Answer 1 · 2014-07-26T04:05:23

The answer is : $y'=-2ln10*x*10^(1-x^2)$

Solution:

let's $y=a^f(x)$ , where a is some constant and $f(x)$ is function of $x$

then, $y'= a^f(x)lna*f'(x)$

Similarly, if we follow this chain rule, we will get

$y'=10^(1-x^2)ln10*(-2x)$

After rearranging, we get

$y'=-2ln10*x*10^(1-x^2)$

How do you find the derivative of y= 10^(1-x^2)y= 10^(1-x^2) ?