Why are there $S_{N} 1$ $"S"_N1$ and $S_{N} 2$ $"S"_N2$ reactions?

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Why are there $S_{N} 1$ $"S"_N1$ and $S_{N} 2$ $"S"_N2$ reactions?

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Answer 1 · 2017-02-07T18:51:14

You might as well ask, $why are there Ford and General Motors?$ $"why are there Ford and General Motors?"$

Explanation:

$S_{N} 1$ $S_(N)1$ and $S_{N} 2$ $S_(N)2$ reactions differ on the basis of mechanism. For an $S_{N} 1$ $S_(N)1$ reaction, $bond breaking$ $"bond breaking"$ is the rate determining step, and the reaction is conceived to proceed thru the intermediacy of a carbocation. On the other hand, for $S_{N} 2$ $S_(N)2$ reactions, bond making is the rate determining step, and the reaction proceeds thru a concerted mechanism in which the geometry of the substrate undergoes inversion upon bond-making. All of this will be explained much better in your organic text.

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Why are there $S_{N} 1$ $"S"_N1$ and $S_{N} 2$ $"S"_N2$ reactions?

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Why are there $S_{N} 1$ $"S"_N1$ and $S_{N} 2$ $"S"_N2$ reactions?