Which quadrants and axes does f(x)=abs(x-6f(x)=|x−6| pass through?

2 Answers
Jake M.
Feb 12, 2018

Both axes and the 1st and 2nd quadrant

Explanation:

We can start by thinking about y=|x|y=|x| and how to transform it into the equation above.

We know the plot of y = |x|y=|x| is basically just a big V with lines going along y = x y=x and y = - xy=−x.

In order to get this equation, we shift xx by 6. In order to get the tip of the V, we would need to plug in 6. However, other than that the shape of the function is the same.

Therefore, the function is a V centered at x = 6x=6, giving us values in the 1st and 2nd quadrants, as well as hitting both the xx and yy axis.

Anthony R.
Feb 12, 2018

The function passes through the first and second quadrants and passes through the yy axis and touches the xx axis

Explanation:

The graph of f(x)=abs(x-6f(x)=|x−6| is the graph of f(x)=abs(xf(x)=|x| shifted 66 units to the right.

Also, this is an absolute function meaning the yy values are always positive so we can say that the range is [0,oo)[0,∞).

Similarly, the domain is (-oo,oo)(−∞,∞)

Given this, the function passes through the first and second quadrants and passes through the yy axis and touches the xx axis.

Here's a picture of the graph below: graph{abs(x-6) [-5.375, 14.625, -2.88, 7.12]}

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