Which of the ordered pairs (6, 1), (10, 0), (6, –1), (–22, 8) are solutions for the equation x + 4y = 10?

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Answer 1 · 2015-07-11T23:38:51

$S={(6,1);(10,0);(-22,8)}$

An ordered pair is solution for an equation when your equality is true for this pair.

Let $x+4y=10$ ,

Is $(6,1)$ a solution for $x+4y=color(green)10$ ?

Replace in the equality $color(red)x$ by $color(red)6$ and $color(blue)y$ by $color(blue)1$

$x+4y=color(red)6+4*color(blue)1color(green)(=10)$

Yes, $(6,1)$ is a solution of $x+4y=10$

Is $(6,-1)$ a solution for $x+4y=10$ ?

Replace in the equality $color(red)x$ by $color(red)6$ and $color(blue)y$ by $color(blue)(-1)$

$x+4y=color(red)6+4*color(blue)((-1))=color(grey)2color(red)!=color(grey)10$

No, $(6,-1)$ isn't a solution of $x+4y=10$

For training, you can check that $(10,0)$ and $(-22,8)$ are solutions of $x+4y=10$ .