Which of the following ordered pairs is a solution of $x + \frac{1}{2} y = 1$ $x + 1/2y = 1$ : $(- 2, 6), (2, - 6), (- 2, - 6)$ $(-2, 6), (2, -6), (-2, -6)$ ?

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Which of the following ordered pairs is a solution of $x + \frac{1}{2} y = 1$ $x + 1/2y = 1$ : $(- 2, 6), (2, - 6), (- 2, - 6)$ $(-2, 6), (2, -6), (-2, -6)$ ?

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Answer 1 · 2016-06-20T11:02:09

$(- 2, 6)$ $(-2,6)$

Explanation:

A solution must obey the algebraic law.

$(- 2, 6) \to - 2 + \frac{6}{2} = 1$ $(-2,6)->-2+6/2=1$ obeys
$(2, - 6) \to 2 + \frac{- 6}{2} \neq 1$ $(2,-6)->2+(-6)/2 ne 1$ does not obey
$(- 2, - 6) \to - 2 + \frac{- 6}{2} \neq 1$ $(-2,-6)->-2+(-6)/2 ne 1$ does not obey

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Which of the following ordered pairs is a solution of $x + \frac{1}{2} y = 1$ $x + 1/2y = 1$ : $(- 2, 6), (2, - 6), (- 2, - 6)$ $(-2, 6), (2, -6), (-2, -6)$ ?

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Which of the following ordered pairs is a solution of x + 1/2y = 1x+12y=1x + 1/2y = 1: (-2, 6), (2, -6), (-2, -6)(−2,6),(2,−6),(−2,−6)(-2, 6), (2, -6), (-2, -6)?

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Which of the following ordered pairs is a solution of $x + \frac{1}{2} y = 1$ $x + 1/2y = 1$ : $(- 2, 6), (2, - 6), (- 2, - 6)$ $(-2, 6), (2, -6), (-2, -6)$ ?