When tanx=1, what does x equal?

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Answer 1 · 2016-05-23T08:15:59

$x = n π + \frac{π}{4}$ $x=npi+(pi)/4$ , where $n$ $n$ is an integer.

$tan x = 1$ $tanx=1$ , but as $tan (\frac{π}{4}) = 1$ $tan(pi/4)=1$

However, as period of tan function is $π$ $pi$ and the function repeats after every $π$ $pi$ ,

the general solution for $tan x = 1 = tan (\frac{π}{4})$ $tanx=1=tan(pi/4)$ is

$x = n π + \frac{π}{4}$ $x=npi+(pi)/4$ , where $n$ $n$ is an integer.