When given line y=2x + 3 and point (4,2), how would you find a parallel and a perpendicular line?

1 Answer

Let say that y=mx+b is the parallel to y=2x+3 from point (4,2)

Hence 2=4m+b where m=2 hence b=-6 so the line is

y=2x-6.

The perpendicular line is y=kx+c where k*2=-1=>k=-1/2 hence

y=-1/2x+c.Because point (4,2) statisfies the equation we have that

2=-1/2*4+c=>c=4

Hence the perpendicular is y=-1/2x+4