Consider the line $y=8x-2$ . What is the equation of the line that is parallel to this line and passes through the point (-5,6)?

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Answer 1 · 2015-11-26T16:36:22

$y=8x+46$

All lines with the same slope are parallel to each other.

All lines with a slope $8$ have equation
$y=8x+C$
where $C$ is some constant.

Let's find a constant $C$ such that point $(-5,6)$ lies on a line:
$6 = 8(-5)+C$
from which follows:
$C = 46$

Therefore, line $y=8x+46$ is parallel to a given line $y=8x-2$ and passes through point $(-5,6)$ .

Consider the line y=8x-2y=8x-2. What is the equation of the line that is parallel to this line and passes through the point (-5,6)?