When 2.00 L of 1.00 M of AgNO_3 and 1.25 L of 1.00 M of CaI_2 fully react, what is the molarity of Ca^2+?

1 Answer
anor277
Jun 24, 2017

For 2AgNO_3(aq) + CaI_2(aq) rarr 2AgI(s)darr + Ca(NO_3)_2(aq)

Explanation:

The calcium ion, Ca^(2+), which is present in solution as (probably) [Ca(OH_2)_6]^(2+), remains in solution, and expresses its concentration fully because it does not precipitate....

"Moles of" Ca^(2+)=1.25*Lxx1.00*mol*L^-1=1.25*mol.

The volume of solution is (2.00+1.25)*L=3.25*L

And thus concentration of calcium ion is............

(1.25*mol)/((2.00+1.25)*L)=0.385*mol*L^-1......

Of course, the silver ion precipitates as a fine yellow powder of AgI.........

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