What would be the cost in dollars of nails for a fence 88 feet long if one needs 9 nails per foot of fence, there are 36 nails in a pound, and they sell for 69 cents per pound?

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What would be the cost in dollars of nails for a fence 88 feet long if one needs 9 nails per foot of fence, there are 36 nails in a pound, and they sell for 69 cents per pound?

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Answer 1 · 2015-02-28T01:07:46

Arrange the ratios so that when multiplied together the units of measurement cancel out (except for the required units of the answer.

$\frac{88 f t}{f e n c e} \times \frac{9 n a i l s}{f t} \times \frac{1 p o u n d}{36 n a i l s} \times \frac{$ 0.69}{1 p o u n d}$ $(88 ft )/(fence)xx(9 nails)/(ft)xx(1 pound)/(36 nails)xx($ 0.69)/(1 pound)$

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$= \frac{$ 14.96}{f e n c e}$ $= ($14.96)/(fence)$

Answer 2 · 2015-02-28T01:09:30

You get:
$88 f t \cdot 9 \frac{n a i l s}{f t} = 792 n a i l s$ $88 ft *9 (nails)/(ft)=792 nails$
$\frac{792 n a i l s}{36 \frac{n a i l s}{p o u n d}} = 22 p o u n d s$ $(792nails)/(36(nails)/(pound))=22 pounds$
$22 p o u n d s \cdot 69 c e n t s = 1518 c e n t s = 15.18 $$ $22pounds*69cents=1518cents=15.18$$

(hope I am right with US units of currency!!!)

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What would be the cost in dollars of nails for a fence 88 feet long if one needs 9 nails per foot of fence, there are 36 nails in a pound, and they sell for 69 cents per pound?

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