What volume of #"NH"_3# at STP is produced if #25.0 "g"# of #"N"_2# is reacted with an excess of #"H"_2# in the reaction #"N"_2 + 3"H"_2 -> 2"NH"_3#?
1 Answer
Mar 16, 2016
Explanation:
Therefore,
#frac{25.0"g"}{28.0 "g/mol"} = 0.893 "mol"#
Each molecule of
Therefore, the 2 times the amount of
#2 xx 0.893 "mol" = 1.79 "mol"#
One mole of an ideal gas has a volume of
Therefore, the volume occupied by
#1.79 "mol" xx 22.4 "L/mol" = 40.0 "L"#
That's it. But bear in mind that you need to somehow remove the excess