What volume of 1.25 M $CaF_2$ solution is needed to provide 4.00 mol $CaF_2$ ?

Question

1953 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-29T19:36:55

3.2 L of 1.25M CaF2

For this problem, you will need to know the formula for molarity.

$Molarity = (mol) / (volume(L))$

or

$M= n/V$

Given:

M = 1.25
n = 4.00 mol

Plug in your given data:

$1.25 = (4.00 mol)/V$

$V$ = 3.2 L

What volume of 1.25 M CaF_2CaF_2 solution is needed to provide 4.00 mol CaF_2CaF_2?