What volume of 1.0 M $CuSO_4$ would you need to make .750 L of a .20 M solution?

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Answer 1 · 2016-05-13T05:29:23

$0.150*L$ are required.

$"Concentration"$ $=$ $"Moles of solute"/"Volume of solution"$ .

And thus $"Moles of solute "(n)$ $=$ $"Concentration "(mol*L^-1)xx"volume "(L)$

In the required volume there are $0.750*Lxx0.20*mol*L^-1$ $=$ $0.150*mol$ .

Thus, in the starting volume, we need $0.150*L$ , which contains $0.150*mol$ . This volume is then diluted to $0.750*L$ .

What volume of 1.0 M CuSO_4CuSO_4 would you need to make .750 L of a .20 M solution?