What value of $b$ makes the polynomial $x^2+ bx+16$ a perfect square?

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Answer 1 · 2016-08-03T11:33:27

$b=+-8$

$x^2+bx+16$ to become perfect square
$b^2-4ac=0$ where $a=1 and c=16$
Therefore
$b^2=4ac$
or
$b^2=4(16)$
or
$b^2=64$
or
$b=+-sqrt64$
or
$b=+-8$

What value of bb makes the polynomial x^2+ bx+16x^2+ bx+16 a perfect square?