What the is the polar form of #y = y/x+(x-2y)^2 #?
1 Answer
Mar 10, 2018
We know that
#rsintheta = (rsintheta)/(rcostheta) + (rcostheta - 2rsintheta)^2#
#rsintheta = tan theta + r^2cos^2theta - 4r^2sinthetacostheta + 4r^2sin^2theta#
Hopefully this helps!
