How do you find the cartesian graph of #r cos(θ) = 9#? Trigonometry The Polar System Converting Between Systems 1 Answer Alan P. Dec 7, 2015 #x=9# Explanation: #cos(theta) = (x_theta)/(sqrt((x_theta)^2+(y_theta)^2))# #r= sqrt((x_theta)^2+(y_theta)^2))# Therefore #color(white)("XXX")rcos(theta) = cancel(sqrt((x_theta)^2+(y_theta)^2))xx (x_theta)/(cancel(sqrt((x_theta)^2+(y_theta)^2))# and since #r*cos(theta) = 9# #color(white)("XXX")x_theta = 9# Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r = 5sin(θ)#? See all questions in Converting Between Systems Impact of this question 8021 views around the world You can reuse this answer Creative Commons License