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What the is the polar form of #y = y/x+x(2-y)^2 #?

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Shwetank Mauria

May 4, 2016

#rsintheta=tantheta+rcostheta(2-rsintheta)^2#

Explanation:

If #(r,theta)# is in polar form and #(x,y)# in Cartesian form the relation between them is as follows:

#x=rcostheta#, #y=rsintheta#, #r^2=x^2+y^2# and #tantheta=y/x#

Hence, #y=y/x+x(2-y)^2# can be written as

#rsintheta=(rsintheta)/(rcostheta)+rcostheta(2-rsintheta)^2#

or #rsintheta=tantheta+rcostheta(2-rsintheta)^2#

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