What's the integral of #int 1/(secx+tanx)dx#?

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What's the integral of #int 1/(secx+tanx)dx#?

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Answer 1 · 2016-03-06T19:14:07

#int 1/(sec x+tan x)d x=l n(1+sin x) + C#

Explanation:

#int 1/(sec x+tan x)d x=(d x)/(1/cos x+sin x/cos x)#
#int (cos x d x)/(1+sin x)" "1+sin x=u" "cos x d x=d u#
#int (d u)/u#
#int 1/(sec x+tan x)d x=l n u +C#
#int 1/(sec x+tan x)d x=l n(1+sin x) + C#

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What's the integral of #int 1/(secx+tanx)dx#?

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