What mass of $C_{12} H_{22} O_{11}$ $C_12H_22O_11$ is needed to make 500mL of 0.200M solution?

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Answer 1 · 2017-03-05T11:33:55

$Concentration$ $"Concentration"$ $=$ $=$ $\frac{Moles of solute}{Volume of solution}$ $"Moles of solute"/"Volume of solution"$

And thus $moles of solute$ $"moles of solute"$ $=$ $=$ $concentration \times volume$ $"concentration "xx" volume"$ :

$=500*cancel(mL)xx10^-3cancelL*cancel(mL^-1)xx0.200*mol*cancel(L^-1)$

$=0.100*mol$ .

And since $"number of moles"$ $=$ $"mass"/"molar mass"$

$"Mass"="moles"xx"molar mass"=0.100*cancel(mol)xx342.29*g*cancel(mol^-1)=??g$

So we need approx. $35*g$ sucrose.

What mass of C_12H_22O_11C12H22O11C_12H_22O_11 is needed to make 500mL of 0.200M solution?