What kind of solutions does $p^2 - 4p + 4 = 0$ have?

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Answer 1 · 2018-04-16T01:37:24

$color(indigo)("The given equation has ONE REAL ROOT, " (p = 2)$

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$D = b^2 - 4ac$

$p^2 - 4p + 4$

$D = b^2 - 4ac = 4^2 - (4 * 1 * 4) = 16 - 16 = 0$

Hence, $color(indigo)("The given equation has ONE REAL ROOT, " (p = 2)$

What kind of solutions does p^2 - 4p + 4 = 0p^2 - 4p + 4 = 0 have?