What is the z-score of X, if mu= 24μ=24, SE =3, and X =31?
1 Answer
Dec 16, 2015
z=2.33z=2.33
Explanation:
z=(x-mu)/(SE)=(31-24)/3=7/3=2.33z=x−μSE=31−243=73=2.33
z=2.33z=2.33
z=(x-mu)/(SE)=(31-24)/3=7/3=2.33z=x−μSE=31−243=73=2.33