What is the z-score of X, if n = 135, $mu= 74$ , SD =3, and X =73?

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Answer 1 · 2016-01-23T20:28:56

$Z= (73-74)/(3/sqrt(135)) = -sqrt(135)/3$

The standard normal distribution simply converts the group of data in our frequency distribution such that the mean is 0 and the standard deviation is 1.

We can use: $z = (x-mu)/sigma$ assuming we have $sigma$
but here we have instead SD = s;

$z = (x- mu)/(s/sqrt(n))$ ; where n is sample size...

What is the z-score of X, if n = 135, mu= 74mu= 74, SD =3, and X =73?