What is the z-score of sample X, if $n = 67, μ = 38, S t . D e v . = 18, and μ_{X} = 76$ $n = 67, mu= 38, St. Dev. =18, and mu_X =76$ ?

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Answer 1 · 2016-11-15T15:59:31

The z-score is $= 17.3$ $=17.3$

The z-score for a sample mean is given by the formula

$z = \frac{¯ x - μ}{\frac{σ}{\sqrt{n}}}$ $z=(barx-mu)/(sigma/sqrtn)$

$¯ x = 76$ $barx=76$

$μ = 38$ $mu=38$

$σ = 18$ $sigma=18$

$n = 67$ $n=67$

Therefore, the z-score $= \frac{76 - 38}{\frac{18}{\sqrt{67}}}$ $=(76-38)/(18/sqrt67)$

$= \frac{38}{2.2} = 17.3$ $=38/2.2=17.3$

What is the z-score of sample X, if n = 67, mu= 38, St. Dev. =18, and mu_X =76n=67,μ=38,St.Dev.=18,andμX=76n = 67, mu= 38, St. Dev. =18, and mu_X =76?