What is the z-score of sample X, if $n = 196, μ = 52, S t . D e v . = 28, and μ_{X} = 49$ $n = 196, mu= 52, St. Dev. =28, and mu_X =49$ ?

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Answer 1 · 2016-11-19T18:51:49

The z-score is $= - \frac{3}{2}$ $=-3/2$

The z-score is $\frac{¯ x - μ}{\frac{σ}{\sqrt{n}}}$ $(barx-mu)/(sigma/sqrtn)$

Here, $¯ x = 49$ $barx=49$

$μ = 52$ $mu=52$

$σ = 28$ $sigma=28$

$n = 196$ $n=196$

The z-score is

$= \frac{49 - 52}{\frac{28}{\sqrt{196}}}$ $=(49-52)/(28/sqrt196)$

$= - \frac{3}{\frac{28}{14}} = - \frac{3}{2}$ $=-3/(28/14)=-3/2$

What is the z-score of sample X, if n = 196, mu= 52, St. Dev. =28, and mu_X =49n=196,μ=52,St.Dev.=28,andμX=49n = 196, mu= 52, St. Dev. =28, and mu_X =49?