What is the z-score of sample X, if $n = 169, μ = 33, S t . D e v . = 39, and E [X] = 37$ $n = 169, mu= 33, St. Dev. =39, and E[X] =37$ ?

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Answer 1 · 2016-11-30T14:48:47

The z-score is $= 1.33$ $=1.33$

The z-score of a sample mean is

$z = \frac{¯ x - μ}{\frac{σ}{\sqrt{n}}}$ $z=(barx-mu)/(sigma/sqrtn)$

Here.

$¯ x = E [X] = 37$ $barx=E [X]=37$

$μ = 33$ $mu=33$

$σ = 39$ $sigma=39$

$n = 169$ $n=169$

$z = \frac{37 - 33}{\frac{39}{\sqrt{169}}}$ $z=(37-33)/(39/sqrt169)$

$= \frac{4}{\frac{39}{13}} = \frac{4}{3} = 1.33$ $=4/(39/13)=4/3=1.33$

Hope this wil help!

What is the z-score of sample X, if n=169,μ=33,St.Dev.=39,andE[X]=37n = 169, mu= 33, St. Dev. =39, and E[X] =37?