What is the y-intercept of 2x-5y =35?

Redirected from "Suppose that I don't have a formula for #g(x)# but I know that #g(1) = 3# and #g'(x) = sqrt(x^2+15)# for all x. How do I use a linear approximation to estimate #g(0.9)# and #g(1.1)#?"
1 Answer
Mar 2, 2018

#(0,-7)#

Explanation:

To find the #y#-intercept of an equation, set #x# equal to #0# and solve:

In the case of #2x-5y=35,# let's replace all instances of #x# in the equation with #0# and solve for #y:#

#2(0)-5y=35#

#-5y=35#

#(cancel(-5)y)/(cancel(-5))=35/-5#

#y=-7#

Thus, the #y#-intercept is at #(x,y)=# #(0,-7).#