What is the weight (in g) of anhydrous Na2CO3 present in 250 mL of 0.25 N solution?

1 Answer
anor277
May 22, 2017

"Concentration"="Moles of stuff"/"Volume of solvent"............

Explanation:

And "mass of stuff"="molar mass"xx"moles of stuff"

So....................

"mass"="molar mass"xx"moles of stuff"xx"volume"xx"concentration".

=105.99*g*cancel(mol^-1)xx0.25*cancel(mol)xx0.250*cancelLxx0.25*cancel(mol)*cancel(L^-1)

="a little under 2 grams"..............

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