What is the vertex of # y=-x^2 + x - 5#?

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What is the vertex of # y=-x^2 + x - 5#?

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Answer 1 · 2016-03-30T23:46:25

#Vertex (1/2, -19/4)#

Explanation:

x-coordinate of vertexL
#x = -b/(2a) = -1/-2 = 1/2#
y-coordinate of vertex:
#y(1/2) = - 1/4 + 1/2 - 5 = - 1/4 - 5 = - 19/4#
#Vertex (1/2, -19/4)#
graph{- x^2 + x - 5 [-20, 20, -10, 10]}

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What is the vertex of # y=-x^2 + x - 5#?

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