What is the vertex of # y= x^2- 6x + 14 #?

1 Answer
Ken C.
Jan 31, 2016

(3, 5)

Explanation:

The x-coordinate of the vertex of a parabola is given by #-b/(2a)#. Remember that parabolas in standard form are #ax^2+bx+c#. With this in mind, we can see that, for our parabola, #a = 1#, #b = -6#, and #c = 14#.

To find the x-coordinate of the vertex, we just plug in the value of #a# and #b# into #-b/(2a)#:

Vertex = #-(-6)/(2(1)) = 6/2 = 3#

Now that we have the #x#, we plug it into our parabola to find #y#:

#(3)^2-6(3)+14 = 9-18+14 = 5#

Our y-coordinate is 5, meaning our vertex is the point (3,5).

Related questions
See all questions in Quadratic Functions and Their Graphs
Impact of this question
4680 views around the world
You can reuse this answer
Creative Commons License