What is the vertex of #y=x^2+3x+5 #? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Nghi N. Jan 10, 2016 #Vertex (-3/2, 11/4)# Explanation: x-coordinate of vertex: #x = -b/(2a) = -3/2# y-coordinate of vertex: #y(-3/2) = (9/4) + 3(-3/2) + 5 = 9/4 - 9/2 + 5 = 11/4# #Vertex (-3/2, 11/4)# Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 2095 views around the world You can reuse this answer Creative Commons License